On electrolysis of aqueous solution of a halide of a metal 'M' by passing 1.5 ampere current for 10 minutes deposits 0.2938 g of metal. If the atomic mass of the metal is 63~gm/mole , then what will be the formula of the metal halide? (A) MCl_{2} (C) MCI (B) MCl_{3} (D) MCl_{4}
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Answer:
60x10=600 sec. 1 I = 1-SA. t= 10 min W = 0.2938 ut Meln M' anche M
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(A)MCl
atomic weight of metal = 7g
q = l × t
= 0.298 × 600
so that, q = 178.8
now as we know that,
eq.wt.of metal = weight of metal/q × F
Eq. wt.of metal = 630×298/1788×15
= 187740/26820
= 7g
As the metal is monovalent , atomic weight of metal will be equal to it's equivalent weight.
Therefore,
Atomic weight of metal = 7g
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