Question

On equations reducible to the form ax - b = cx+d
6. Solve for x:
(a) (x - 1)(x + 4) = (x-2)(x+8)
8x-1
(b)
52-1 10x 1
31+€ 2x-3
(d)
2+2 2x + 3
(c)
1
x + 3
x-2
x²​

Answer 1

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$(a)(x - 1)(x + 4) = (x - 2)(x + 8) \\ \implies {x}^{2} + 4x - x - 4 = {x}^{2} + 8x - 2x - 16 \\ \implies \: {x}^{2} - {x}^{2} + 3x - 6x = - 16 + 4 \\ \implies - 3x = - 12 \\ \implies \: x = \frac{12}{3} = 3$

Answer 2

Step-by-step explanation:

(a) (x-1)(x+4) = (x-2)(x+8)

→ x² + 3x - 4 = x² + 6x - 16

→ - 4 + 16 = 6x - 3x

→ 12 = 3x

→ x = 4

The other two questions are not understandable..

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