On evaporation of 2.72 g of saturated solution of a substance, we obtained 0.72 g precipitate. the solubility of substance would be???
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Answered by
3
Hello Dear.
Good Question and your answer is here.
Given---
Mass of Solution = 2.72 grams
Mass of Solute (Precipitates) = 0.72 grams.
Mass of Solvent = Mass of Solution - Mass of Solute
= 2.72 - 0.72
= 2 grams.
Using the Formula,
Solubility% = (Mass of Solute/Mass of Solvent) × 100%
= (0.72/2) × 100%
= 0.36 × 100%
= 36 %
Thus, the Solubility of the Substance would be 36%.
I anticipate it will help u.
Have a Marvelous Day.
Good Question and your answer is here.
Given---
Mass of Solution = 2.72 grams
Mass of Solute (Precipitates) = 0.72 grams.
Mass of Solvent = Mass of Solution - Mass of Solute
= 2.72 - 0.72
= 2 grams.
Using the Formula,
Solubility% = (Mass of Solute/Mass of Solvent) × 100%
= (0.72/2) × 100%
= 0.36 × 100%
= 36 %
Thus, the Solubility of the Substance would be 36%.
I anticipate it will help u.
Have a Marvelous Day.
Answered by
3
Solubility :- an amount of solute that can dissolve in given amount of solvent.
In simple way, solubility =
Here , mass of solute ( precipitates) = 0.72 g
mass of solvent = mass of solution - mass of solute = 2.72 - 0.72 =2 g
now, solubility = 0.72/2 × 100 = 72/2 = 36
Hence solubility of substance is 36.
In simple way, solubility =
Here , mass of solute ( precipitates) = 0.72 g
mass of solvent = mass of solution - mass of solute = 2.72 - 0.72 =2 g
now, solubility = 0.72/2 × 100 = 72/2 = 36
Hence solubility of substance is 36.
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