on factor of x⁴+x²=1
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⇒ (x²)² + x² - (1)² = 0
By Sreedharacharya's method
roots = {-1 (+/-) √(1 + 4)}/2
= -1 +/- √5 /2
= (-1 + √5)/2 and (-1 - √5)/2
By Sreedharacharya's method
roots = {-1 (+/-) √(1 + 4)}/2
= -1 +/- √5 /2
= (-1 + √5)/2 and (-1 - √5)/2
mdaftabrain:
Plz give me the generally answer. I have a most impont
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