Math, asked by shobhit15082006, 7 months ago

On factorising x2 + (p + 1/p) x + 1, we get

Answers

Answered by sheenujsph
1

Find zeros of the equation x^2 + x-p(p+1)

So first step would be to make it in the form of a quadratic equation in simple form.

We get,   x^2 + x-p (p+1) = 0

X^2 + x – p^2 –p = 0

X(x + 1) –p(p-1) = 0

So it is obvious that either x (x + 1) = 0 or – p (p-1) = 0

So x = 0 or p = 0.

Now for verification we plug in values of x = 0 or p = 0 in equations we get..

0 + 0 -0(0+1) = 0

0 + 0 – 0 – 0 = 0

L.H.S = R.H.S.

Answered by jaskiratsinghsethi64
0

Answer:

L.H.S = R.H.S.

Step-by-step explanation:

Find zeros of the equation x^2 + x-p(p+1)

So first step would be to make it in the form of a quadratic equation in the simple form.

We get,   x^2 + x-p (p+1) = 0

X^2 + x – p^2 –p = 0

X(x + 1) –p(p-1) = 0

So it is obvious that either x (x + 1) = 0 or – p (p-1) = 0

So x = 0 or p = 0.

Now for verification we plug in values of x = 0 or p = 0 in equations we get..

0 + 0 -0(0+1) = 0

0 + 0 – 0 – 0 = 0

L.H.S = R.H.S.

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