Math, asked by azoya4693, 19 days ago

on February 2 a person deposited rs 10000 in savings account at 6% per anum the rate of interest was reduced to 5% on 28 June and it was raised to 51/2% on 9 September find the amount payable to the depsiter on 21 November.​

Answers

Answered by ShadowLove
3

Answer:

Time= Feb+mar+Apr+May+June

=26+31+30+31+28

=146

S.I.= PRT/100

=10000×6×146 by 100×365

= 240

Time = June+July+aug+sep

=2+31+31+9

= 73

S.I. = PRT/100

= 10000×5×73 by 100× 365

= 100

Time = sep+Oct+Nov

= 21+31+21

=73

S.I. = PRT/100

=10000×11×73 by 100×2×365

= 110

Total of S.I. = 240+ 100+ 110= 450

A = P+I = 10000+450 = 10450 ans completed

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