Question

On finding values of trigonometrical ratios and expressions

1. (a) If sin A =root 3 /2


find the value of: (i) cos A (ii) cot A + cosec A
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Answer 1

sinA=√3/2

sinA=sin60°

A=60°

cosA=cos60°=1/2

• cotA+cosecA
• cot60°+ cosec60°
• 1/√3 + 2/√3
• (1+2)/√3
• 3/√3*√3/√3
• √3

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