Question

On heating 0.220g of a metallic oxide in presence of hydrogen, 0.045g of water is

formed. If the equivalent mass of the metal is E then what is the value of

9​

Answer 1

Answer:

4

Explanation:

Let the metallic oxide be MO

MO + H2 -----> H2O + M

Now, by law of equivalence,

equivalence of MO = equivalence of H2O

weight of MO/Equivalent weight of MO = weight of H2O/equivalence of H2O

0.22/ E + 8 = 0.045 / 9

On solving you will get,

E = 36

E/9 = 36/9 = 4