on heating 1.763 gram of hydrated BaCl2 to dryness 1.505 gram of anhydrous salt remained. Hence the formula of hydrated salt will be?? (atomic no of Ba = 137)
Answers
Mass of hydrated BaCl2 = 1.763g
Mass of dry BaCl2 = 1.505 g
Mass of Water = 1.763 - 1.505 = 0.258g
Number of moles of water = 0.25818=0.014
Number of moles of BaCl2=1.505208=0.007
Ratio of moles of BaCl2 to water = 0.007 : 0.014 = 1:2
∴ formula of the hydrated salt = BaCl2.2H2O
Answer:
Hey mishra ji
listen go to basics of chemistry. there could be many sln :
1.USING POAC
Explanation:in this method u neednt to balance eqn ,directly equalise the atoms
2.USING CONCEPT : just use empiracal formulae concept to find out in one line u will get 1:2 =bacl2:h2o . or3.BY % RULE :take h2o as x and find out % w/w and equalise it with the given info . problem solving is a nice process just make ur concepts strong and u will solve all questions of stichiometry and mole concept ,eudiometry easily .Hope this will motivate and help uuu