On heating 13.15g of niso4.Yh2o of the anhydrous salt was obtained determine the value of y
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Explanation:
We start with the HYDRATE of a nickel salt...
N
i
S
O
4
⋅
n
(
H
2
O
)
(
s
)
+
Δ
→
N
i
S
O
4
(
s
)
+
n
H
2
O
(
g
)
↑
⏐
We heat the nickel hydrate such that we are left with nickel sulfate, and the mass loss represents the moles of water...
Moles of nickel sulfate (anhydrous)
=
77.5
⋅
g
154.75
⋅
g
⋅
m
o
l
−
1
=
0.501
⋅
m
o
l
...
But the mass LOST represented the water present....
Moles of water lost
=
140.5
⋅
g
−
77.5
⋅
g
18.01
⋅
g
⋅
m
o
l
−
1
=
3.50
⋅
m
o
l
...and so we divide thru by the LOWEST molar quantity to get...
(
N
i
S
O
4
)
0.501
⋅
m
o
l
0.501
⋅
m
o
l
⋅
(
O
H
2
)
3.50
⋅
m
o
l
0.501
⋅
m
o
l
≡
(
N
i
S
O
4
)
⋅
(
O
H
2
)
7
..
And so we got...
N
i
S
O
4
⋅
(
O
H
2
)
7
...a salt of nickel sulfate with SEVEN waters of crystallization....
hope it's helpful ❤❤
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