Question

On heating 3.526 g of hydrated BaCl2 to dryness,3.010 g of anhydrous salt remained.Hence the formula of the hydrate is (Atomic weight of Ba = 137) (1) BaCl2.1/2H2O (2) BaCl2.H2O (3) BaCl2.2H2O (4) BaCl2.5H2O​

Answer 1

Answer:

BaCl2.2H2O will be the formulae of the hydrate.

Explanation:

Since, we know that the mass of hydrated BaCl2 is 3.526g and the  mass of the dry BaCl2 as given is 3.010 g.

So, we know that the mass of water will be = 3.526 – 3.010 = 0.516 g.

So, the number of moles of the water will be = 0.516/18 = 0.028.

So, number of moles of BaCl2 will be = 3.010/208= 0.014.

Hence, the ratio of the moles of BaCl2 to the water will be = 0.014 : 0.0 28.

Which on solving we will get = 1:2.

Accordingly, the formula of hydrated salt will be = BaCl2.2H2O.