Question

On heating 4.9 of kclo3 shows a weight loss of 0.384. what percent of original kclo3 has been decomposed

Answer 1

$here \: is \: the \: answer$


↪Equation: -⤵
==========

2KClO3 →heat→ 2KCl + 3O2 

⭐2mol KClO3 will produce 2mol KCl and 3 mol O2 

Molar mass KClO3 = 122.55 g/mol 

Molar mass O2 = 32g/mol 

0.384g mass loss = 0.384g O2 produced 

Mol O2 produced = 0.384/32

= 0.012 mol O2 

↪This means that 0.012*2/3 = 0.008 mol KClO3 decomposed 

Mass of 0.008 mol KClO3 = 122.55* 0.008

= 0.980g KClO3 decomposed 

% KClO3 that decomposed = 0.980/4.9 *100


$so \: the \: percentage \: is \: 20.0\%$

$hope \: it \: helps$


$\beta e \: \beta \gamma \alpha inly$

Answer 2

Heya



Here is ur ans dear⭐⭐


refer to this attachment ⭐⭐



$hope \: it \: helps \: u$