On heating a mixture of potassium dichromate and sodium chloride with concentrated sulphuric acid in a dry test tube, the compound formed
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4NaCl(s) + K2Cr2O7(s) + 3H2SO4(l) ⟶ Δ
K2SO4{Potassium sulphate} + 2NaSO4{Sodium sulphate}+ 2CrO2Cl2{Chromyl chloride, Orange red} + 3H2O
Answer: Chromyl chloride
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