Question

On heating the three oxides of lead in a curent of hydrogen,the following results were obtain.
1. 393g of lithage gives 1.293of lead.
2.173g of lead peroxide gives 1.882g of lead.
1.712g of red lead gave 1.552 of lead.
Show that these results are agreementwith the law of multiple proportion.​

Answer 1

Answer:

Weight of PbO=1.393,

Weight of Pb=1.293,

Weight of O2=1.393−1.293=0.1g

0.1gofO2 combines with 1.293gofPb

1gofO2 combines with 1.2930.1=12.93gofPb

b. Weigth of PbO2=2.173g

Weight of Pb=1.882g

Weight of O2=2.173−1.882gofPb

0.291gofO2=1.882gpfPb

1gofO2=1.8820.291=6.46gofPb

c. Weight of Pb3O4=1.712g

Weight of Pb=1.552g

Weight of O2=1.712−1.552=0.16gofO2

∴0.16gofO2=1.552gofPb

1gofO2=1.5520.16=9.7gofPb

Therefore, weight of Pb in three cases whicc combines with a fixed mass (1g) of (O2)

=12.93:6.46:9.7

=12.936.46=6.466.46:9.76.46

Hence, the law of multiple proposition is verfied.

Alternatively, the weight of O2 in three cases which combines with a fixed mass of Pb can also be calculated and they will also bear a simple whole number ratio, which proves law of multiple proportion.

Explanation: