Chemistry, asked by meemanjumehta7777, 6 months ago

On heating vapours of S8(g) decomposes to S2(g). Due to this, the van-der Waal's constant 'b' for the
resulting gas.
(A) increases
(B) decreases
(C) remains same. (D) changes unpredictably

Answers

Answered by rohan721

1

Vander wall forces should be decrease

Answered by nithingangishetty50

0

Explanation:

Volume of S8 is more than S2. Therefore 'b' decreases.

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