Question

On horizontal surface of truck a block of mass 1kg is placed coefficient of friction is 0.6 the truck is accelerating with 5m/s^2 then friction on block is

Answer 1

Answer:

Explanation:

mass of the block = 1kg

acceleration of the truck = 5 m/s²

pseudo force acting on the block = ma = 1×5 = 5N

coefficient of static friction = 0.6

maximum value of static friction = μmg = 0.6×1×10 = 6N

Friction is a self adjusting force. It can vary from 0 to its maximum value when a force acts on it. So when a force acts on a body, friction starts acting in the opposite direction. And movement of the body will not be there untill the force acting on it exceeds the maximum friction.

Here the force acting on it is 5N which is less than maximum friction(6N). So the friction will be 5N.

Note: maximum friction is 6N. friction is 5N.

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Answer 2

Answer:

5N

Explanation:

Frictional force = μmg

                         = 0.6 x 1 x 10

                         = 6 N

since applied force is less than 6N friction acting will be equal to applied force 5N