On immersing a solid sphere in a cuboidal tank with base area 792 cm^2, the water level in the tank rose from 25 cm to 74 cm. What is the radius of the sphere? (Assume the value of π as 22/7.)
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Answer:
21 cm
Step-by-step explanation:
Base Area of Cuboid = 792 cm^2 (l x b)
Original water level in tank = 25 cm
New water level = 74 cm
Difference in water level = 74 - 25
= 49 cm (h)
Let radius of sphere be R cm
4πR^3/3 = lbh
R^3 = 792 X 49 X 3 X 7 / 22 X 4
R^3 = 3^3 X 7^3
Thus R = 21 cm
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