Question

on increasing each of radius of the base and height of the cone by 20% its volume will be increased by​

Answer 1

Answer:

20percent os volume will increase

Answer 2

Answer:

72.8

Step-by-step explanation:

$v = \frac{1}{3} \pi {r}^{2} h \\ \\ given \: \: r \: and \: h \: are \: increased \: by \: 20\% \\ \\ r = 1.2r \\ \\ h = 1.2h \\ \\ v {}^{l} = \frac{1}{3} \pi {1.2r}^{2} (1.2)h \\ \\ {v}^{l} = {(1.2)}^{3} v \\ \\ {v}^{l} = 1.728v \\ \\ {v}^{l} = v + 0.728v \\ \\ v \: increased \: by \: 72.8\%$

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