on increasing the mass of a body suspended at the end of a spring kept vertically its period
Answers
Answered by
12
hey there !!
◆ suppose a body of mass "m" is suspended by spring of spring constant 'k'
...|
...|
...|
...|
[ m ]
=) we know that weight 'mg' acting downward and spring elongates 'x' so spring force ' kx' developed which balances the weight .
=) so here , kx = mg ---------(1)
now again spring is displaced x' from mean position
now equivalent force is
=). F = -(k( x+x') - kx )
=) so F = - kx'
here this is condition S.H.M
for this particle executing S.H.M .
=) Time period (T) = 2π√m/k
so , here we can see that :
time period is directly proportional to mass ..on increasing mass time period also increases ...
_____________________________
Hope it will help u
◆ suppose a body of mass "m" is suspended by spring of spring constant 'k'
...|
...|
...|
...|
[ m ]
=) we know that weight 'mg' acting downward and spring elongates 'x' so spring force ' kx' developed which balances the weight .
=) so here , kx = mg ---------(1)
now again spring is displaced x' from mean position
now equivalent force is
=). F = -(k( x+x') - kx )
=) so F = - kx'
here this is condition S.H.M
for this particle executing S.H.M .
=) Time period (T) = 2π√m/k
so , here we can see that :
time period is directly proportional to mass ..on increasing mass time period also increases ...
_____________________________
Hope it will help u
Answered by
0
Answer:
increases
because T is proportional to d
Explanation:
Similar questions