On independence day the students of a school of a school represented a drill . There were 2x-1 rows of students and in each there were 2x+3 students. If 1024 students took part in the drill , find the number of rows of students . Which values are exhibited by the students?
Answers
Answered by
19
Hi,
Here
We have to solve this a little concept
As you know
Number of rows of students × number of students in each row = total number of students
Here,
Number of rows of students = 2x - 1
And
Number of students in each row = 2x + 3
Therefore
(2x - 1)(2x + 3) = 1024
At last
We get x = 15.5
Therefore
Number of rows = 2x - 1 = 2(15.5) - 1
=30
Therefore the answer is 30
The value depicted by students is displine
Bye
Hope you liked it
Mark me brainliest
Here
We have to solve this a little concept
As you know
Number of rows of students × number of students in each row = total number of students
Here,
Number of rows of students = 2x - 1
And
Number of students in each row = 2x + 3
Therefore
(2x - 1)(2x + 3) = 1024
At last
We get x = 15.5
Therefore
Number of rows = 2x - 1 = 2(15.5) - 1
=30
Therefore the answer is 30
The value depicted by students is displine
Bye
Hope you liked it
Mark me brainliest
Answered by
28
Answer:
Hii
2^x-1>÷2^x+3=1024
2^x-1-x+3=2^6+2^4
X-1-x+3=6+4[base same]
X+2=10
X=10-2
X=8
No. Of rows is 8
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