on introducing a thin film in the path of one of the two interfering beam,the central fringe will shift by one fringe width. if refractive index =1.5, the thickness of the film is (wavelength of monochromatic light is lambda
a)4 lambda
b)3 lambda
c)2 lambda
d)1 lambda
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Answer:
2λ
Explanation:
Shift = Δ€
Width of one fringe = λ
Δ€=(μ−1)t=1λ
For one maximum shift :
t× (μ−1)=λ
=} t×(1.5-1)=λ
=} t= 2 λ
t = thickness of the thin film
λ = wavelength of monochromatic light
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