On january 22, 1943, the temperature in spearfish, south dakota, rose from - 4.0 ∘f to 45.0 ∘f in just 2 minutes. what was the temperature change in celsius degrees?
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Answered by
2
Problem 1: 3.80+44.8 = 48.6 F
C=(F-32)/1.8
C=(44.8-32)/1.8 = 7.11 C
C = 12.8/1.8 = 7.11 C
K = 280.11 K
Problem 2:
37.89 C
310.89 K
C=(F-32)/1.8
C=(44.8-32)/1.8 = 7.11 C
C = 12.8/1.8 = 7.11 C
K = 280.11 K
Problem 2:
37.89 C
310.89 K
Answered by
1
......................7.11°C
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