Question

On loading a metal wire of cross section 10
mand length 2m by a mass of 210 kg it
extends by 16mm and suddenly broke from
the point of support. If density of that metal is
8000 kgm and its specific heat is 420 Jkg-
K-' the rise in temperature of wire is
(g = 10 ms)
0​

Answer 1

Answer:Energy=21​×stress×strain×volume

            =21​×AF​×lΔl​×pm​

            =21​×10−62100​×1000×216​×8000210​

specific heat × temperature×mass=energy

420×t×210=21​×10−62100​×1000×216​×8000210​

t=2×4201​×10

Explanation:

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Answer 2

Answer:

2.5°c

Explanation:

energy= 1/2× stress × strain @ volune

= 1/2 × f/h × delta L/l × m/p

= 1/2 × 2100/10'-6 × 16/1000×2 × 210/1000

SH× TEMP × MASS = ENERGY

420 × t × 210= 1/2 × 2100/10'-6 ×16/1000×2 × 210/8000

t = 1/2×420 × 2100/10'-6 × 16/1000×2 × 1/8000

= 2.5°c