On mixing two classes A and B of students having average marks 25 and 40 respectively, the overall average obtained is 30. Find the ratio of the students in the classes A and B.
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Answered by
3
Let the number of students in class A is x and class of B be yWe have to find x:y=x/y
Average marks of class A
[tex]25= \frac{Sum of A}{x} [/tex]
Similarly,
Adding both sums,
According to the question
[tex]Average of A and B= \frac{Sum of A + Sum of B}{x+y} [/tex]
THUS
[tex]-5x=-10y [/tex]
ANS:
x:y=2:1
Average marks of class A
[tex]25= \frac{Sum of A}{x} [/tex]
Similarly,
Adding both sums,
According to the question
[tex]Average of A and B= \frac{Sum of A + Sum of B}{x+y} [/tex]
THUS
[tex]-5x=-10y [/tex]
ANS:
x:y=2:1
Answered by
0
Answer:2:1
Step-by-step explanation:
average marks of class A=25 (A1)
average marks of class B=40(A2)
overall average is obtained=30 (Aw)
ratio of the student in classes A and B = n1/n2 = (A2-Aw)/(Aw-A1)
n1/n2 = 10/5
n1:n2 = 2:1
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