Math, asked by Sakshee99, 1 year ago


On mixing two classes A and B of students having average marks 25 and 40 respectively, the overall average obtained is 30. Find the ratio of the students in the classes A and B.


Akv2: Average... based... question...

Answers

Answered by Kmg13teen
3
Let the number of students in class A is x and class of B be yWe have to find x:y=x/y

Average marks of class A



= \frac{Sum of A}{Number of students  in A }


[tex]25= \frac{Sum of A}{x} [/tex]




25x = Sum of A


Similarly,


40y=Sum of B
Adding both sums,

25x+40y=Sum of A + Sum of B





According to the question


[tex]Average of A and B= \frac{Sum of A + Sum of B}{x+y} [/tex]


30(x+y)= Sum of A + Sum of B



Sum of A + Sum of B = 30x+30y


THUS


25x+40y=30x+30y

[tex]-5x=-10y [/tex]


 \frac{x}{y} = \frac{2}{1}
ANS:
x:y=2:1


Answered by robinsharma972001
0

Answer:2:1

Step-by-step explanation:

average marks of class A=25 (A1)

average marks of class B=40(A2)

overall average is obtained=30 (Aw)

ratio of the student in classes A and B = n1/n2 = (A2-Aw)/(Aw-A1)

n1/n2 = 10/5

n1:n2 = 2:1

Similar questions