Math, asked by shankarrockstar3703, 11 months ago

On monday the value of a company share was 7.50 rs the price increased by 6% on tuesday, decreased by 1% on Wednesday, and decreased by 2% on Thursday.Find the value of each share when trade opened on friday.

Answers

Answered by usha7424
7
3/*X=7.50
X=750*100/10*6
X=7500/6
X=1150/3
Answered by mathsdude85
13

<b><i><u>Answer :</u>

The value of a company’s shares on Monday = Rs. 7.50

To find the value of a company’s shares on Tuesday,

Value on Monday = Rs. 7.50

% Increase = 6% of 7.50

\to\dfrac{6}{100}×7.50

= 0.45

<u>Value on Tuesday = Value on Monday + value on Increase percentage</u>

= 7.50+0.45

= Rs. 7.95

∴ The Value on Tuesday is Rs. 7.95

To find the value of a company’s shares on Wednesday,

Value on Tuesday = Rs. 7.95

% decrease = 1.5% of 7.95

\to\dfrac{1.5}{100}×7.95

= 0.11925

<u>Value on Wednesday = Value on Tuesday - value on decrease percentage</u>

= 7.95-0.11925

= Rs. 7.83075

∴ The Value on Wednesday is Rs. 7.83075

Value on Thursday = Rs. 7.83075

% decrease = 2% of 7.83075

\to\dfrac{2}{100}×7.83075

= 0.156

Value on Thursday = Value on Wednesday - value on decrease percentage

= 7.83075-0.156

= \bold{\boxed{Rs. 7.674}}

∴ The Value on Thursday is Rs. 7.674

The value of share when opened on Friday is equal to the Thursday’s closing price.

<u>The opening Value of the share on Friday is Rs. 7.674

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