On on selling a TV at 5% gain and a fridge at 10% gain A shopkeeper gains rupees 3250 but if he sells the TV at 10% gain and a fridge at 5% loss he gains rupees 1500 find the actual price of TV and that of the fridge.
Answers
Let, the price of a TV be Rs.x and that of a fridge be Rs.y
Then, we have:
100
5x
+
100
10y
=2000
5x+10y=200000
⇒x+2y=40000
⇒x=40000−2y....(i)
Now,
100
10x
−
100
5y
=1500
⇒10x−5y=150000
⇒2x−y=30000
⇒2(40000−2y)−y=30000 from euation (i)
⇒80000−4y−y=30000
⇒5y=80000−30000
⇒y=
5
50000
⇒y=Rs10000
∴x=Rs40000−Rs20000
⇒x=Rs.20000
∴ Price of a T.V. =Rs.20000
Price of a fridge =Rs10000
Hope it will help you
Please mark me as brainlist and follow me
Answer:
Let the actual price of the TV be Rs. 'x' and of the fridge be Rs. 'y'
Situation -1
By selling the TV at 5 % gain and fridge at 10 % gain, the shopkeeper gains Rs. 2000.
5x/100 + 10y/100 = 2000
→ x/20 + y/10 = 2000/1
Taking the L.C.M. of the denominator and then solving it, we get.
- (x + 2y)/20 = 2000
X + 2y = 40000
Situation - 2
By selling the TV at 10 % gain and fridge at 5 % loss, the shopkeeper gains Rs. 1500. The loss is indicated with the negative sign.
- 10x/100 - 5y/100 = 1500
→ x/10 - y/20 = 1500/1
Taking the L.C.M. of the denominator and then solving it, we get.
→ (2x - y)/20 = 1500
» 2x - y = 30000
.(2)
Now, multiplying the (1) by 2, and then subtracting 2 from it, we get.
First Multiplying (1) by 2 = 2"[(x + 2y) = 40000]
- 2x + 4y = 80000
Now, subtracting (2) from the above.
2x + 4y = 80000 2x у + = 30000
Бу
= 50000
5y = 50000
» y = 50000/5
» y = 10000
The actual price of fridge is Rs. 10000. Now putting the value of y = 10000 in (1), we get
→ x + 2y = 40000
→ x + (2*100O0) = 40000
→ x = 40000 - 20000
→ x = 20000
Hence, the actual price of TV is Rs. 20000 and actual price of fridge is Rs. 10000.
Step-by-step explanation:
Hope it will help