On one day a rickshaw puller earned Rs 160. Out of his earnings he spent Rs 133/5 on tea and
snacks, Rs 101/2 on food and Rs 82/5 on repairs of the rickshaw. How much did he save on that day?
Answers
Answered by
9
Answer:
We know that the given details are
Total earnings =Rs.160
Earnings spent on tea and snacks =Rs.26
5
3
Earning spent on food =Rs.50
2
1
Earnings sped on repairs =Rs.16
5
2
∴ Total expenditure = Earnings spent on tea and snacks + Earnings spent on food + Earnings spent on repairs
=Rs.26
5
3
+Rs.50
2
1
+Rs.16
5
2
=
5
133
+
2
101
+
5
82
By taking LCM for 5 and 2 is 10
=
10
(133×2+101×5+82×2)
=
10
(266+505+164)
=
10
935
Total Savings = Total Earnings − Total Expenditure
=Rs.160−Rs.
10
935
By taking 10 as the LCM
=
10
(160×10−935×1)
=
10
(1600−935)
=
10
665
=66
2
1
∴ Total Savings on that day is Rs.66
2
1
.
Step-by-step explanation:
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