Math, asked by sisodiadeepika4, 1 month ago

On one day a rickshaw puller earned Rs 160. Out of his earnings he spent Rs 133/5 on tea and

snacks, Rs 101/2 on food and Rs 82/5 on repairs of the rickshaw. How much did he save on that day?​

Answers

Answered by sukhpreetkaur82405
9

Answer:

We know that the given details are

Total earnings =Rs.160

Earnings spent on tea and snacks =Rs.26

5

3

Earning spent on food =Rs.50

2

1

Earnings sped on repairs =Rs.16

5

2

∴ Total expenditure = Earnings spent on tea and snacks + Earnings spent on food + Earnings spent on repairs

=Rs.26

5

3

+Rs.50

2

1

+Rs.16

5

2

=

5

133

+

2

101

+

5

82

By taking LCM for 5 and 2 is 10

=

10

(133×2+101×5+82×2)

=

10

(266+505+164)

=

10

935

Total Savings = Total Earnings − Total Expenditure

=Rs.160−Rs.

10

935

By taking 10 as the LCM

=

10

(160×10−935×1)

=

10

(1600−935)

=

10

665

=66

2

1

∴ Total Savings on that day is Rs.66

2

1

.

Step-by-step explanation:

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