on one mole of gas at s.tp. is doubled and the temperature is raised to 546 K. What is the
The pressure
)
final volume of the gas? (one mole of a gas occupies a volume of 22.4 litres at stp.)
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Step-by-step explanation:
P1=760 mmhg P2=760×2=1520
V1=22.4L V2=?
T1=273K T2=2×273=546K
By using gas eqaution
P1V1/T1 = P2V2/T2
760×22.4/273 = 1520×V2/546
V2= 760×224×546/273×1520×10
= 112/5
= 22.4×2
V2 =5017.6
HOPE THIS WILL HELP YOU
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