On one of the longer sides pq of a rectangle pqrs a point x is taken such that sx2 = px x pq
Answers
Answered by
23
Answer:
Given
sx = px . pq
=> sx .sx = px.pq
=>
∵ pq= sr
=>
∠pxs = ∠rsx (alternate angle)
so sx/sr = px/sx and ∠pxs = ∠rsx
=> Δpxs is similar to Δxsr
(hence proved)
============
@GauravSaxena01
Attachments:
Similar questions