Question

on passing 3 ampere of electricity for 50 minutes 1.8 gram metal deposits the equivalent weight of a metal is​

Answer 1

Explanation:

We know that

Charge = Current×time (time should be considered in seconds)

Hence Q= I× t

therefore Q= 3×50×60 = 9000 coloumb

so when you supply 9000 C , 1.8 gram of metal gets deposited

and when you supply 96500 C(which is ≈ 1farad), the mass of metal deposited is equal to its equivalent mass(E)

Hence, we cross multiply:

9000C----1.8gram

96500C----?

hence Equivalent mass= (96500×1.8)÷9000 = 19.3gram