Question

On passing C ampere of electricity through a electrolyte
solution for t second. m gram metal deposits on cathode.
The equivalent weight E of the metal is
(a) E = C × t/m × 96500
(b) E = C × m/t × 96500
(c) E = 96500 × m/C × t
(d) E = C × t × 96500/m

Answer 1

Answer:

(b) E=C×m/t ×96500

Explanation:

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Answer 2

The equivalent weight E of the metal is

(c) E = 96500 × m/(C × t )

The mass of metal deposited on cathode (m) is given as:

m = (E*C*t)/96500

where,

E = Equivalent weight of metal,

C = Current passed in Ampere

t = time elapsed in seconds

So, E = (96500*m)/(C*t)

So, option (C) is correct.