Question

On passing C ampere of electricity through a electrolyte solution for t second. m gram metal deposits on cathode. The equivalent weight E of the metal is
(a) $E = \frac{C x t}{m x 96500}$
(b) $E = \frac{C x m}{t x 96500}$
(c) $E = \frac{m x 96500}{C x t}$
(d) $E = \frac{C x t x 96500}{m}$

Answer 1

${\huge {\mathfrak {Answer :-}}}$

➡️ Option (D)

That's it..

Answer 2

Thanks for your question ✌

OPTION D IS CORRECT ✔✔

THANKS