Question

On passing current through two cells, connected in series containing solution of AgNO₃ and CuSO₄, 0.18 g of Ag is deposited. The amount of the Cu deposited is:
(a) 0.529 g
(b) 10.623 g
(c) 0.0529 g
(d) 1.2708 g

Answer 1

$<b>$
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$\mathbb{NICE...QUESTION}$

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→ [B]

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Answer 2

(a) 0.529 g is the proper answer.

Faraday's Second Law:

• Faraday's Second Law of Electrolysis states that the mass of a substance deposited or liberated at any electrode on passing a sure quantity of rate is at once proportional to its chemical equal weight.

Explanation:

• From the faradays 2nd law, m1/m2 = eq1/eq2
• ⇒0.18/m2 = (108/1)/(63.5/2)
• ∴m2= 0.0529g

The quantity of the Cu deposited is 0.0529g.

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