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The surface area of the right pyramid having square base of side 18 cm and vertical height 12 cm is
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Length of the side of the base(square)=10cm
Height of the pyramid=12cm
As it is a right prism the line dropped
from the top of the pyramid falls on the
base making an angle of 90°
We can use the Pythagorean theorem
Slant height 2-base^2+height^2
Slant height ^2-5^2+12^2
Slant height=√25+144=√169-13
Total surface area=p*h/2+b
P is the perimeter of the base-4*10=40
H is the slant height=13
B is the area of a base=100
Total surface
area=40*13/2+100=520/2+100=260+100= 360
Total surface area=360cm^2
Lateral surface area-total surface area
area of base
360-100=260cm^2
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