Question

On rationalising the denominator of 1/ 2+ root3 , we get

Answer 1

Answer:

2-√3

Step-by-step explanation:

1/2+√3

1 (2-√3)

(2+√3) (2-√3)

2-√3

(2)²-(√3)²

2-√3

4-3

2-√3

1

2-√3

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Answer 2

Answer:

$\frac{1}{2 + \sqrt{3} } \\ \\ \frac{1}{ 2 + \sqrt{3} } \times \frac{2 - \sqrt{3} }{2 - \sqrt{3} } \\ \\ \frac{2 - \sqrt{3} }{4 - 2 \sqrt{3} + 2 \sqrt{3} - \sqrt{9} } \\ \\ \frac{2 - \sqrt{3} }{4 - \sqrt{9} } \\ \\ \frac{2 - \sqrt{3} }{4 - 3 } \\ \\ \frac{2 - \sqrt{3} }{1 } \\ \\ = 2 - \sqrt{3} \: \: answer$

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