Question

on rationalizing the denominator of 1/√7-√6

Answer 1

$\frac{1}{ \sqrt{7} - \sqrt{6} } \\ \\ = \frac{1}{ \sqrt{7} - \sqrt{6} } \times \frac{ \sqrt{7} + \sqrt{6} }{ \sqrt{7} + \sqrt{6} } \\ \\ = \frac{ \sqrt{7} + \sqrt{6} }{ {( \sqrt{7}) }^{2} - {( \sqrt{6}) }^{2} } \\ \\ = \frac{ \sqrt{7} + \sqrt{6} }{7 - 6} \\ \\ \frac{ \sqrt{7} + \sqrt{6} }{1} \\ \\ = \sqrt{7} + \sqrt{6}$

Answer 2

Hope it helps !!!.......