Question

on rationalizing the denominator of 1/√7-√6, we get

Answer 1

Answer:

$(\sqrt{7} + \sqrt{6} ).$

Step-by-step explanation:

$\frac{1}{ \sqrt{7} - \sqrt{6} } \times \frac{ \sqrt{7} + \sqrt{6} }{ \sqrt{7} + \sqrt{6} } = \frac{ \sqrt{7} + \sqrt{6} }{ { \sqrt{7} }^{2} - { \sqrt{6} }^{2} } = \frac{ \sqrt{7} + \sqrt{6} }{7 - 6} = \frac{ \sqrt{7} + \sqrt{6} }{1}$