on rationalizing the denominator of 3/(√2-√5) we get
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2(√3+√5)/(√3-√5)*(√3+√5)
2(√3+√5)/(√3-√5)*(√3+√5)
=(2√3+2√5)2(√3+√5)/(√3-√5)*(√3+√5)
=(2√3+2√5)=(√3+√5) ANSWER
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