on rationalizing the denominator of 3√3/
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2√8
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Answered by
7
3√3/2√8
= 3√3/2√8 × 2√8/2√8
= 6√24 ur answer
hope it's helps you..☺✍✍✔
= 3√3/2√8 × 2√8/2√8
= 6√24 ur answer
hope it's helps you..☺✍✍✔
Answered by
5
Answer :
![given \: = \: \frac{3 \sqrt{3} }{2 \sqrt{8} } \\ \\ = > \: simplify \: the \: root \: \\ \\ = > \: \frac{3 \sqrt{3} }{4 \sqrt{2} } \\ \\ = > \: rationalize \: the \: denomintor \: by \: \\ \\ = > \: multiplying \: \sqrt{2} with \: denominator \: and \: numerator \\ \\ = > \: \frac{3 \sqrt{3} \sqrt{2} }{4 \sqrt{2} \sqrt{2} } \\ \\ = > \: \frac{3 \sqrt{2 \times 3} }{4 \times 2} \\ \\ = > \: \frac{3 \sqrt{6} }{8} \\ \\ = > \: 0.918559 given \: = \: \frac{3 \sqrt{3} }{2 \sqrt{8} } \\ \\ = > \: simplify \: the \: root \: \\ \\ = > \: \frac{3 \sqrt{3} }{4 \sqrt{2} } \\ \\ = > \: rationalize \: the \: denomintor \: by \: \\ \\ = > \: multiplying \: \sqrt{2} with \: denominator \: and \: numerator \\ \\ = > \: \frac{3 \sqrt{3} \sqrt{2} }{4 \sqrt{2} \sqrt{2} } \\ \\ = > \: \frac{3 \sqrt{2 \times 3} }{4 \times 2} \\ \\ = > \: \frac{3 \sqrt{6} }{8} \\ \\ = > \: 0.918559](https://tex.z-dn.net/?f=given+%5C%3A+%3D+%5C%3A+%5Cfrac%7B3+%5Csqrt%7B3%7D+%7D%7B2+%5Csqrt%7B8%7D+%7D+%5C%5C+%5C%5C+%3D+%26gt%3B+%5C%3A+simplify+%5C%3A+the+%5C%3A+root+%5C%3A+%5C%5C+%5C%5C+%3D+%26gt%3B+%5C%3A+%5Cfrac%7B3+%5Csqrt%7B3%7D+%7D%7B4+%5Csqrt%7B2%7D+%7D+%5C%5C+%5C%5C+%3D+%26gt%3B+%5C%3A+rationalize+%5C%3A+the+%5C%3A+denomintor+%5C%3A+by+%5C%3A+%5C%5C+%5C%5C+%3D+%26gt%3B+%5C%3A+multiplying+%5C%3A+%5Csqrt%7B2%7D++++++++with+%5C%3A+denominator+%5C%3A+and+%5C%3A+numerator+%5C%5C+%5C%5C+%3D+%26gt%3B+%5C%3A+%5Cfrac%7B3+%5Csqrt%7B3%7D+%5Csqrt%7B2%7D+%7D%7B4+%5Csqrt%7B2%7D+%5Csqrt%7B2%7D+%7D+%5C%5C+%5C%5C+%3D+%26gt%3B+%5C%3A+%5Cfrac%7B3+%5Csqrt%7B2+%5Ctimes+3%7D+%7D%7B4+%5Ctimes+2%7D+%5C%5C+%5C%5C+%3D+%26gt%3B+%5C%3A+%5Cfrac%7B3+%5Csqrt%7B6%7D+%7D%7B8%7D+%5C%5C+%5C%5C+%3D+%26gt%3B+%5C%3A+0.918559)
Hope it would help you
Hope it would help you
ritikboss833:
mujse kya problem h apko??
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