Question

on rationalizing the denominator of
$1 \ \div \sqrt{3} - \sqrt{2}$
We get

$1. \: \sqrt{ 3 } + \sqrt{2}$
$1. \sqrt{3 } + \sqrt{2 } \div 5$
$3. \: \: \sqrt{3} \div \sqrt{2}$
$4.none \: of \: these \:$

Answer 1

Answer:

answer is option(a) √3 + √2

Step-by-step explanation:

1/(√3 - √2)

1/(√3 - √2) × (√3 + √2)/(√3 + √2)

(√3 + √2)/[(√3 - √2)(√3 + √2)

(√3 + √2)/[(√3)² - √2)²]

(√3 + √2)/[3 - 2]

(√3 + √2)/1

√3 + √2