Math, asked by sanky7654, 8 months ago

on rationslising the denominater of 3/3root2-2root3 we get ?​

Answers

Answered by Anonymous
0

Answer:

3/3√2-2√3

3(3√2+2√3)/(3√2-2√3)(3√2+2√3)

using (a-b)(a+b)=a²-b²

3(3√2+2√3)/(3√2)²-(2√3)²

3(3√2+2√3)/36-12

3(3√2+2√3)/24

32+23

8

therefore ,

after rationalising denominator=8

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