On reaching the top of a slope 6 m high from its bottom, a cyclist has a speed of 1.5 ms -1. Find the kinetic energy and the potential energy of the cyclist. The mass of the cyclist and his bicycle is 40 kg.
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Answer:
KE = 45 J
PE =2352 J
Explanation:
Given
h = 6m : ,m=40kg : v=1.5m/s : g=9.8
KE = mv²/2 = 40 x 1.5 x 1.5 / 2 = 45 J
PE = mgh = 40 x 9.8 x 6 = 2352 J
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