On real axis if a=1-5 and b=3-9, then A-B is
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Step-by-step explanation:
9(25a2+b2)+25(c2−3ac)=15b(3a+c)
225a2+9b2+25c2−75ac=45ab+15bc
225a2+9b2+25c2−75ac−45ab−15bc=0
(15a)2+(2b)2+(5c)2−(15a)(5c)−(15a)(3b)−(3b)(5c)=0
(15a)2+(2b)2+(5c)2=(15a)(5c)+(15a)(3b)+(3b)(5c)
15a=3b=5c=k
b=5a and c=3a
Hence, a=15k, b=3k and c=5k
∴b−a=154k
and
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