Question

On reversing the digits of a two digit number, number obtained is 9 less than three times the original number. If difference of these two numbers is 45, find the original
number.
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Answer 1

Answer:

The two digit number is 27.

Step-by-step explanation:

Let x be the tens digit's of the number and y be the unit's digit of the number.

Then, original number = 10x + y

On reversing the digits, the number becomes = 10y + x

According to the problem,

⇝ 10y + x = 3(10x + y) -9

⇝ 10y + x = 30x + 3y - 9

⇝ 7y - 29x = - 9 → (1)

Also given,

⇝ 10y + x -(10x + y) = 45

⇝ 9y - 9x = 45

⇝ y - x = 5

⇝ y = 5 + x → (2)

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Substitute (2) in (1) we get,

⇝ 7(5 + x) -29x = -9

⇝ 35 + 7x - 29x = -9

⇝ - 22x = - 44

⇝ x = 2

Substituting the value of x in (2) ⇒

y = 5 + 2 = 7

∴ The number is 27.

Answer 2

ORIGINAL NUMBER IS 27

ᴋᴇᴇᴘ ǫᴜᴇsᴛɪᴏɴɪɴɢ ᴀɴᴅ ʙᴇ ᴀ ʙʀᴀɪɴʟɪᴇsᴛ.

ᴛʜᴀɴᴋ ʏᴏᴜ