Math, asked by sharmasanvi556611, 1 month ago

On reversing the digits of a two digit number, number obtained is 9 less than three times

the original number. If difference of these two numbers is 45, find the original number.

Answers

Answered by tennetiraj86
2

Step-by-step explanation:

Given :-

On reversing the digits of a two digit number, number obtained is 9 less than three times the original number. and difference of these two numbers is 45.

To find :-

Find the original number ?

Solution :-

Let the digit in the 10's place in the two digit number be X

The place value of X = 10X

Let the digit in the 1's place in the two digit number be Y

The place value of Y = Y

The original two digit number = 10X+Y

On reversing the digits in the two digit number then the new number = 10Y+X

Given that

On reversing the digits of a two digit number, number obtained is 9 less than three times

the original number.

=> New number = 3× Original number - 9

=> 10Y+X = 3(10X+Y)-9

=> 10Y+X = 30X+3Y-9

=> 30X+3Y-10Y-X = 9

=> (30X-X) +(3Y-10Y) = 9

=> 29X +(-7Y) = 9

=> 29X -7Y = 9 ----------(1)

and

The diference of these two numbers = 45

=> New number - Original number = 45

=> (10Y+X) -(10X+Y) = 45

=> 10Y+X-10X-Y = 45

=> (10Y-Y)+(X-10X) = 45

=> 9Y-9X = 45

=>9(Y-X) = 45

=> Y-X = 45/9

=> Y-X = 5

=>Y = 5+x ---------(2)

On substituting the value of Y in (1) then

=> 29X -7Y = 9

=> 29X -7(5+X) = 9

=> 29X -35-7X = 9

=> (29X-7X)-35 = 9

=> 22X -35 = 9

=> 22X = 9+35

=> 22X = 44

=> X = 44/22

=> X = 2

And

On substituting the value of X in (2) then

=> Y = 5+2

=> Y = 7

Therefore ,X = 2 and Y = 7

The digit at 10's place = 2

The digit at 1's place = 7

Then the number = 27

Answer:-

The required original number for the given problem is 27

Check :-

Original number = 27

The new number obtained by reversing the digits= 72

Their difference = 72-27 = 45

New number = 72

=> 81-9

=> (3×27)-9

=> 3×Original number -9

New number = 3×Original number -9

Verified the given relations in the given problem.

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