Question

on selling a bucket at 19.50 rupees a shopkeeper earn 30% profit so to earn 40% profit he sale the bucket at​

Answer 1

$\textbf{\underline{\underline{Answer :-}}}$

The bucket should be sold at Rs. 21 to get Profit of 40%

$\textbf{\underline{\underline{Explanation :-}}}$

$\textsf{\underline{\underline{Given :}}}$

Selling Price of the bucket = Rs.19.50 when

Profit = 30%

$\textsf{\underline{\underline{To find : }}}$

The Selling Price for profit % = 40%

$\textsf{\underline{\underline{Solution :}}}$

$\textbf{Case I}$

▪ Selling Price = Rs.19.5

▪ Profit % = 30%

▪ Cost Price = ?

❖ We know :

${\boxed{\sf\:{\orange{CP = \frac{100}{(100+Profit\%)} \times SP}}}}$

$\sf{\implies} \: CP = \dfrac{100}{100 + 30} \times 19.5$

$\sf{\implies} \: CP = \dfrac{100}{130} \times 19.5$

$\sf{\implies} \: CP = \dfrac{1950}{130}$

$\sf{\purple{\implies}} \: \orange{CP = 15}$

Cost Price = Rs.15

$\textbf{Case II}$

▪ Cost Price = Rs.15 (from above)

▪ Profit % = 40%

▪ Selling Price = ?

❖ We know :

${\boxed{\sf\:{\orange{SP = \frac{(100 + profit\%)} {100} \times CP}}}}$

$\sf{\implies} \: SP = \dfrac{100 + 40}{100} \times 15$

$\sf{\implies} \: SP = \dfrac{140}{100} \times 15$

$\sf{\implies} \: SP = \dfrac{2100}{100}$

$\sf{\implies} \: SP = \dfrac{21 \: {\cancel{00}}}{1 \: {\cancel{00}}}$

$\sf{\purple{\implies}} \: {\orange{SP = 21}}$

$\therefore$ The bucket should be sold at Rs. 21 to get Profit of 40%

Answer 2

The bucket should be sold at Rs. 21 to get Profit of 40%

Selling Price of the bucket = Rs.19.50 when

Profit = 30%

The Selling Price for profit % = 40%

▪ Selling Price = Rs.19.5

▪ Profit % = 30%

▪ Cost Price = ?

❖ We know :

Cost Price = Rs.15

▪ Cost Price = Rs.15 (from above)

▪ Profit % = 40%

▪ Selling Price = ?

❖ We know :

The bucket should be sold at Rs. 21 to get Profit of 40