Math, asked by samritmukherjee14, 8 months ago

On selling a tea set at 5% loss and a lemon set at 15% gain, a shopkeeper gains 70.
If he sells the tea set at 5% gain and lemon set at 10% gain, he gains 130. Find the
cost price of the lemon set.​

Answers

Answered by alibarmawer
22

Answer:

Solution:-

Let the cost of tea set be Rs 'x' and the cost of lemon set be Rs 'y'.

The shopkeeper sells a tea set at 5 % loss and a lemon set ate 15 % gain.

So, the loss on tea set = x*5/100

And the gain on lemon set = y*15/100

Total gain = 15y/100 - 5x/100 = 70

15y - 5x = 7000

Dividing it by 5, we get

3y - x = 1400 

-x + 3y = 1400...........(1)

If he sells the tea set at 5 % gain and lemon set at 10 % gain, he gains Rs 130.

Therefore,

5x/100 + 10y/100 = 130

5x + 10y = 13000

Dividing it by 5, we get

x + 2y = 2600 ..............(2)

Adding (1) and (2), we get

- x + 3y = 1400

 x + 2y = 2600

______________

     5y = 4000

______________

y = 4000/5

y = 800

Substituting the value of y = 800 in (2), we get

x + 2y = 2600

x + 2*800 = 2600

x + 2600 - 1600 

x = 1000

So the cost price of tea set is Rs 1000 and the cost price of lemon set is Rs 800.

hope it helps

thanks

Answered by varun021976
6

Step-by-step explanation:

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