Math, asked by bhavyajain2914, 9 months ago

On selling a tea set at 5% loss and a lemon set at 15% gain, a crockery seller gains 7. If he sells the tea set at 5% gain and lemon set at 10% gain, he gains 13. Find the actual price of the tea set.

Answers

Answered by anonymous6338
19

Let the cost of tea set be Rs 'x' and the cost of lemon set be Rs 'y'.

The shopkeeper sells a tea set at 5 % loss and a lemon set ate 15 % gain.

So, the loss on tea set = x*5/100

And the gain on lemon set = y*15/100

Total gain = 15y/100 - 5x/100 = 70

15y - 5x = 7000

Dividing it by 5, we get

3y - x = 1400

-x + 3y = 1400...........(1)

If he sells the tea set at 5 % gain and lemon set at 10 % gain, he gains Rs 130.

Therefore,

5x/100 + 10y/100 = 130

5x + 10y = 13000

Dividing it by 5, we get

x + 2y = 2600 ..............(2)

Adding (1) and (2), we get

- x + 3y = 1400

x + 2y = 2600

______________

5y = 4000

______________

y = 4000/5

y = 800

Substituting the value of y = 800 in (2), we get

x + 2y = 2600

x + 2*800 = 2600

x + 2600 - 1600

x = 1000

So the cost price of tea set is Rs 1000 and the cost price of lemon set is Rs 800.

MARK BRAINLIEST PLEASE

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