Math, asked by amanchhikara744, 10 months ago

On selling an article for 115,the gain is 20% more than the loss incurred on selling it on 104.If the article is sold for 130.80,then the profit percentage is:​

Answers

Answered by ChitranjanMahajan
2

On selling an article at rs 130.80, the percentage of profit gained by the seller is 140.22 %

• Let the cost price (C.P.) of the article be rs x.

• When the article is sold (S.P.) at rs 104,  the loss incurred = C.P. - S.P. = rs (x - 104)

• When the article is sold (S.P.) at rs 115, there is gain of rs (115 - x) .

• According to the question,

(115 - x) = 20 % of (x - 4) + (x - 4)

=> (115 - x) = (20/100) ( x - 4) + (x - 4)

=> 115 - x = (x - 4) {(1/5) + 1}

=> 115 - x = (6/5) ( x - 4)

=> 5( 115 - x) = 6( x - 4)

=> 575 - 5x = 6x - 24

=> 6x + 5x = 575 + 24

=> 11x = 599

=> x = 599 / 11

=> x = 54.45

Therefore, the C.P. of the article is rs 54.45 .

• Given, the article is sold (S.P.) at rs 130.80 .

Therefore, profit = S.P. - C.P. = rs (130.80 - 54.45)

=> Profit = rs 76.35

• Therefore profit % = (profit / C.P.) × 100

=> Profit % = (76.35 / 54.45) × 100 %

=> Profit % = 140.22 %

Answered by bhagyashreechowdhury
0

If the article is sold for Rs. 130.80, then the profit percentage is 20%.

Step-by-step explanation:

Let the cost price of the article be Rs. “x”.

When the Selling price of the article = Rs. 115,  the gain is = S.P. - C.P. = Rs. (115 - x)

When the Selling Price of the article = Rs. 104, the loss is = C.P. – S.P. = Rs. (x - 104)  

Now,

According to the question, we can write the equation as,

(115 - x) = [20 % of (x - 104)] + (x - 104)

⇒ (115 - x) = [1/5 * ( x - 104)] + (x - 104)

⇒ 115 - x = x/5 – 20.8 + x – 104

⇒ 115 + 20.8 + 104 = 2x + x/5

⇒ 239.8 * 5 = 10x + x

⇒ 1199 = 11x

⇒ x = 1199/11

x = Rs. 109 the C.P. of the article

Here given the Selling price of the article = Rs. 130.80

Thus,

The profit percentage is given by,

= [(S.P. - C.P.)/C.P.] * 100

= [(130.80 - 109)/109] * 100

= [21.8/109] * 100

= 20%

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