On selling an article for 115,the gain is 20% more than the loss incurred on selling it on 104.If the article is sold for 130.80,then the profit percentage is:
Answers
On selling an article at rs 130.80, the percentage of profit gained by the seller is 140.22 %
• Let the cost price (C.P.) of the article be rs x.
• When the article is sold (S.P.) at rs 104, the loss incurred = C.P. - S.P. = rs (x - 104)
• When the article is sold (S.P.) at rs 115, there is gain of rs (115 - x) .
• According to the question,
(115 - x) = 20 % of (x - 4) + (x - 4)
=> (115 - x) = (20/100) ( x - 4) + (x - 4)
=> 115 - x = (x - 4) {(1/5) + 1}
=> 115 - x = (6/5) ( x - 4)
=> 5( 115 - x) = 6( x - 4)
=> 575 - 5x = 6x - 24
=> 6x + 5x = 575 + 24
=> 11x = 599
=> x = 599 / 11
=> x = 54.45
Therefore, the C.P. of the article is rs 54.45 .
• Given, the article is sold (S.P.) at rs 130.80 .
Therefore, profit = S.P. - C.P. = rs (130.80 - 54.45)
=> Profit = rs 76.35
• Therefore profit % = (profit / C.P.) × 100
=> Profit % = (76.35 / 54.45) × 100 %
=> Profit % = 140.22 %
If the article is sold for Rs. 130.80, then the profit percentage is 20%.
Step-by-step explanation:
Let the cost price of the article be Rs. “x”.
When the Selling price of the article = Rs. 115, the gain is = S.P. - C.P. = Rs. (115 - x)
When the Selling Price of the article = Rs. 104, the loss is = C.P. – S.P. = Rs. (x - 104)
Now,
According to the question, we can write the equation as,
(115 - x) = [20 % of (x - 104)] + (x - 104)
⇒ (115 - x) = [1/5 * ( x - 104)] + (x - 104)
⇒ 115 - x = x/5 – 20.8 + x – 104
⇒ 115 + 20.8 + 104 = 2x + x/5
⇒ 239.8 * 5 = 10x + x
⇒ 1199 = 11x
⇒ x = 1199/11
⇒ x = Rs. 109 ← the C.P. of the article
Here given the Selling price of the article = Rs. 130.80
Thus,
The profit percentage is given by,
= [(S.P. - C.P.)/C.P.] * 100
= [(130.80 - 109)/109] * 100
= [21.8/109] * 100
= 20%
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