On sides AB and DC of rectangle ABCD, points F and E are chosen such that AFCE is a rhombus. If AB is equal to 16 cm and BC is equal to 12 cm Then find EF.
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According to question
AB = 16
BC = 12
In triangle ABC
by pythagoras theorem
AC^2 = AB^2 + BC^2
AC^2 = 16^2 + 12^2
AC^2 = 256+ 144
AC = 20
We know the diagonals of a rhombus are equal
Thus AC = EF = 20 Cm
Thus EF = 20 Cm
AB = 16
BC = 12
In triangle ABC
by pythagoras theorem
AC^2 = AB^2 + BC^2
AC^2 = 16^2 + 12^2
AC^2 = 256+ 144
AC = 20
We know the diagonals of a rhombus are equal
Thus AC = EF = 20 Cm
Thus EF = 20 Cm
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