Question

On sides AB and DC of rectangle ABCD, points F and E are chosen such that AFCE is a rhombus. If AB is equal to 16 cm and BC is equal to 12 cm Then find EF.

Answer 1

According to question

AB = 16
BC = 12

In triangle ABC
by pythagoras theorem

AC^2 = AB^2 + BC^2
AC^2 = 16^2 + 12^2
AC^2 = 256+ 144
AC = 20

We know the diagonals of a rhombus are equal

Thus     AC = EF =  20 Cm
Thus EF =  20 Cm